Insulation R-Value and U-Value Calculator

List each layer of the wall, roof or floor with its thickness and thermal conductivity (λ). The calculator adds the layer resistances and the surface resistances to give RSI in m²·K/W, the U-value in W/m²·K and the US R-value. 100 mm of insulation at λ 0.035 plus 12.5 mm board at λ 0.25 gives RSI 3.08, U 0.325 and R-17.5.

Measurements

Units
Layers (inside to outside)

0.17 m²·K/W is commonly used for walls (0.13 + 0.04). Use your standard's values.

Results

Thermal resistance (RSI)

3.08 m²·K/W

U-value

0.325 W/m²·K

R-value (US)
17.5 ft²·°F·h/BTU
Show the working
  1. Layer resistance (d ÷ λ)#1: 0.0125 m ÷ 0.25 W/m·K = 0.05 m²K/W
  2. Layer resistance (d ÷ λ)#2: 0.1 m ÷ 0.035 W/m·K = 2.857 m²K/W
  3. TotalΣ + 0.17 = 3.077 m²K/W · U = 1 ÷ 3.077 = 0.325 W/m²K · R = 3.077 ÷ 0.1761 = 17.5
Paper and orientation
Open the list

How to use the R-value calculator

  1. Choose Imperial or Metric for layer thicknesses; conductivity is always in W/m·K.
  2. Add each layer from inside to outside with its thickness and thermal conductivity λ.
  3. Enter the surface resistances for your element.
  4. Read the RSI, U-value and US R-value.

How the calculation works

Each layer’s resistance is R = thickness ÷ λ. The total RSI is the sum of the layer resistances plus the surface resistances. U-value = 1 ÷ RSI. US R-value = RSI ÷ 0.1761. Open Show the working to see each layer’s contribution.

Worked examples

Insulated stud bay (clear field). 12.5 mm board (λ 0.25): 0.05. 100 mm insulation (λ 0.035): 2.857. Surfaces: 0.17. Total RSI 3.08, U-value 0.325 W/m²·K, R-17.5.

Single layer. 100 mm of insulation at λ 0.04 with no surface resistances: RSI 2.5, U 0.4, about R-14.2.

How to interpret the results

Compare the U-value or R-value with the requirement in your energy code, which may apply to the whole assembly including thermal bridging. A lower λ or a thicker layer both raise RSI; doubling the thickness doubles that layer’s resistance.

Tips and common mistakes

  • Use declared λ values, not generic ones, for compliance work.
  • Don’t add air gaps as insulation unless they are sealed and you know their resistance.
  • Compressed insulation performs worse than its rated thickness suggests.
  • Thermal bridges through studs, joists and fixings lower the real-world value.

Improving an existing wall or roof

Adding a layer changes the total in a predictable way: each new layer adds its own thickness ÷ λ to the RSI. Try adding a row to see how much an extra layer of insulation board or a thicker batt improves the U-value before you buy. Diminishing returns are real: the first layers make the biggest difference to heat loss.

Assumptions and limitations

This is a simplified layer-by-layer calculation. Official calculations for building regulations follow standards such as EN ISO 6946 and account for bridging, fixings and moisture.

Frequently asked questions

What is the difference between R-value and U-value?

R-value measures resistance to heat flow (higher is better). U-value is heat loss per square metre per degree of temperature difference (lower is better). For a simple layered build-up, U = 1 ÷ total RSI.

How do I convert RSI to US R-value?

One US R-value unit (ft²·°F·h/BTU) equals about 0.1761 m²·K/W. Divide RSI by 0.1761 to get the US R-value; RSI 3.08 is about R-17.5.

How is the resistance of a layer calculated?

Divide the layer thickness in metres by its thermal conductivity λ in W/m·K. 100 mm of insulation with λ 0.035 has a resistance of 0.1 ÷ 0.035 = 2.86 m²·K/W.

Where do I find thermal conductivity?

Manufacturers publish the declared λ value on product data sheets. Use the declared value for the exact product you plan to install.

What are surface resistances?

The thin layers of still air on each side of a surface add a little resistance. 0.17 m²·K/W (0.13 inside + 0.04 outside) is a common value for walls with horizontal heat flow; roofs and floors use different values.

Does it account for studs or thermal bridges?

No. It calculates a clear-field value through the layers. Timber or steel studs reduce the effective value, sometimes considerably.

Sources